if A=45 prove that cos2A=cos Asquare-sinAsquare

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Dileep Vishwakarma

2 years ago

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Aditya Raj Verma

2 years ago

Cos2A = Cos²A - Sin²A A = 45° LHS:- Cos2(45)° Cos 90°. #(Cos 90°=0) 0 RHS:- Cos²45° - Sin²45° 1/√2 - 1/√2 0 hence proved LHS=RHS

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