The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration. K equilibrium is (a) 2.5 (b) 2.0 (c) 0.5 (d) 1.5
Solution : The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration `K_("equlibrium")` is 2 because the reaction is reversible. So `K=(K_(1))/(K_(2))=2/1=2.
