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Geeta Pandey

Class 10th
Maths
2 years ago
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Question 20. The average kinetic energy of the molecules of a gas at 27°C is 9 10-20 J. what is its average K.E. at 227°C? (a) 5 10-20 J (b) 10 10-20 J (c) 15 10-20 J (d) 20 10-20 J Answer

1 Answer
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Dileep Vishwakarma

2 years ago

Correct option is C) Mean KE=23kT​ so 6.21×10−21=3k×300/2 so k=1.38×10−23 KE at 500 K ,KE=3×1.38×10−23×500/2=10.35×10−21 Joule

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