A jet airplane travelling at the speed of 500 km/h ejects its products of combustion at the speed of 1500 km/h relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?
Relative velocity VA/B=vA−vB given VA/B=1500Km/h vA−vB=1500 vA−(−500)=1500 Since the velocity of combustion products and plane are in opposite directions VA=1000km/h
