user image

Ananya Shree

Class 11th
Physics
2 years ago

A jet airplane travelling at the speed of 500 km/h ejects its products of combustion at the speed of 1500 km/h relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?

user image

Muskan Anand

2 years ago

Relative velocity VA/B​=vA​−vB​ given VA/B​=1500Km/h vA​−vB​=1500 vA​−(−500)=1500 Since the velocity of combustion products and plane are in opposite directions VA​=1000km/h

Recent Doubts

Close [x]