A cricketer can throw a ball to a maximum horizontal distance of 100 m. How much high above the ground can the cricketer throw the same ball?
Maximum horizontal distance, R=100m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., =45∘. The max horizontal range for a projection velocity v is given by the relation: Rmax=gu2 100=gu2 The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a=g Using the third equation of motion: v2−u2=−2gH H=u2/2g=100/2=50m
