The cylindrical tube of a spray pump has a cross-section of 8.0 cm2 one end of which has 40 fine holes each of diameter 1.0 mm. If the liquid flow inside the tube is 1.5 m min–1, what is the speed of ejection of the liquid through the holes?
The cross-section area of the cylindrical tube A1=8cm2 =8×10−4m2 The speed of the liquid flow inside the tube V1=1.5 m/minute =601.5ms−1 Area of each hole =π(0.5×10−3)2 m2 Area of 40 holes A2=40π(0.5×10−3)2m2 A1V1=A2V2 V2=A2A1V1 =40π×(0.5×10−3)2×608×10−4×1.5=0.636ms−1.
