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Ananya Shree

Class 11th
Chemistry
2 years ago

Calculate the oxidation number of all the atoms in- CrO42-.

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Muskan Anand

2 years ago

If x is the ox. no. of Cr in CrO42- ion then x + 4 × (- 2) x = – 2 x = 8 – 2 = 6 x = 6 For O → 6 + 4(x) = – 2 4x = – 8 x = −84 = – 2

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