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Deepika Deepika

Class 11th
Physics
2 years ago

please answer

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Abhishek Mishra

2 years ago

Since all the equations are for the displacements of the particle, they all should have the dimension of the length. Now, checking all the equations of displacement to be dimensionally correct. (a) Since the tignometric functions are dimensionless, T 2πt ​ will also be dimensionless. T 2πt ​ = T T ​ =1=[M 0 L 0 T 0 ] Here, a is the amplitude and it will have the dimension of the length. SO, the equation is correct.(b) Since the tignometric functions are dimensionless, vt should be dimensionless. vt=(LT −1 )(T)=L=[M 0 L 1 T 0 ] Thus, the given equation is not correct. (c) The quantity a t ​ should be dimensionless a t ​ = L T ​ =[M 0 L −1 T 1 ] Therefore, it is also dimensionally incorrect. (d) The tignometric functions are dimensionless, T 2πt ​ will also be dimensionless.2πt ​ = T T ​ =1=[M 0 L 0 T 0 ] The given equation is dimensionally correct. Thus, the formulas in (b) & (c) are dimensionally wrong.

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