Explain how much portion of an atom located at (i)corner and (ii)body-centre of a cubic unit cell is part of its neighbouring unit cell.
(i)An atom positioned on the nook of a cubic unit mobileular is shared with the aid of using 8 adjoining unit cells. Therefore, 1/8th part of the atom is shared through one unit cell. (ii)An atom positioned on the frame centre of a cubic unit mobileular isn't always shared through its neighbouring unit mobileular. Therefore, the atom belongs most effective to the unit mobileular wherein it's far gift i.e., its contribution to the unit cell is 1.
