Energy of an electron in the ground state of the hydrogen atom is -2.18 x 10 -18 J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol -1 .
It is given that the energy of an electron in the ground state of the hydrogen atom is –2.18 × 10 –18 J. Therefore, the energy required to remove that electron from the ground state of hydrogen atom is 2.18 × 10 –18 J. Ionization enthalpy of atomic hydrogen = 2.18 × 10 –18 J Hence, ionization enthalpy of atomic hydrogen in terms of J mol –1 = 2.18 × 10 –18 × 6.02 × 10 23 J mol –1 = 1.31 × 10 6 J mol –1
