Explain quantitatively the order of magnitude difference between the diamagnetic susceptibility of N2 and Cu.
We know that Density of nitrogen ρN2=28g22.4L=26g22400ccρN2=28g22.4L=26g22400cc Also, density of copper ρCu=8g22.4L=8g22400ccρCu=8g22.4L=8g22400cc Now, comparing both densities ρN2ρCu=2822400×18=1.6×10−4ρN2ρCu=2822400×18=1.6×10-4 Also given XN2XCu=5×10−910−5=5×10−4XN2XCu=5×10-910-5=5×10-4 We know that, X=Magnetisation(M)Magnetic intensity(H)X=Magnetisation(M)Magnetic intensity(H) =Magnetic moment(M)/volume(V)H=Magnetic moment(M)/volume(V)H =MHV=MH(mass/density)=MpHm=MHV=MH(mass/density)=MpHm X=ρ(∵MHm=constant)X=ρ(∵MHm=constant) Hence, XN2XCu=ρN2ρCu=1.6×10−4XN2XCu=ρN2ρCu=1.6×10-4 Thus, we can say that magnitude difference or major difference between the diamagnetic susceptibility of N2N2 only Cu.
