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Ananya Shree

Class 12th
Physics
2 years ago

Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

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Muskan Anand

2 years ago

Initial current, I1​=5.0A Final current, I2​=0A Change in current, dl=I1​−I2​=5A Time taken for the charge, t=0.1s Average emf, e=200V For self inductance(L) of the coil, we have the relation for average emf as: e=Ldtdi​ L=dtdi​e​ =0.15​=4H200​ Hence the self inductance of the coil is 4H.

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