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Ananya Shree

Class 12th
Physics
2 years ago

A neutron beam of energy E scatters from atoms on a surface with a spacing d = 0.1nm. The first maximum of intensity in the reflected beam occurs at θ = 30°. What is the kinetic energy E of the beam in eV?

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Muskan Anand

2 years ago

Here, d=0.1nm,θ=30∘,n=1d=0.1nm,θ=30∘,n=1. According to Bragg's law 2dsinθ=nλor2×0.1×sin30∘=1×λorλ=0.1nm=10−10m2dsinθ=nλor2×0.1×sin30∘=1×λorλ=0.1nm=10-10m p=hλ=6.62×10−3410−10=6.62×10−24kgms−1p=hλ=6.62×10-3410-10=6.62×10-24kgms-1 KE=12p2m=12×(6.62×10−24)21.67×10−27J=12(6.62×10−24)2(1.67×10−27)×(1.6×10−19)eV=0.082eV

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