What is the minimum energy that must be given to an H atom in ground state so that it can emit an Hγ line in Balmer series? If the angular momentum of the system is conserved, what would be the angular momentum of such Hγ photon?
We know that Hγ spectral line in Balmer series formed when electron falls from n=5 to n=1. Here the electron is in ground state i.e., n=1 and must be taken to n=5 for Hγ line. So the energy=E5−E1=[5213.6]−(−13.6)=−0.54+13.6=13.06eV Since angular momentum is conserved, so the angular momentum of Hγ = change in angular momentum of electron = L5−L2 = 5h - 2h =3h=3×6.63×10−34=19.89×10−34kgm2/s
