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Ananya Shree

Class 12th
Chemistry
2 years ago

The concentration of cation vacancies in NaCl crystal doped with CdCl2is found to be 6.02 x 1016mol-1. What is the concentration of CdCl2added to it?

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Muskan Anand

2 years ago

1 mole = 6.023 × 10236.023 × 1023 CdCl2CdCl2 creates = 1 mole of vacancy. So, 1 CdCl2CdCl2 creates = 16.022 × 102316.022 × 1023 vacancy Now, 6.022 × 10166.022 × 1016 creates = x vacancy. So, the percentage of CdCl2CdCl2 added will be: 6.022 × 1023 × x100= 6.022 × 10166.022 × 1023 × x100= 6.022 × 1016   x = 10-5   mol of CdCl2

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