A stone of mass 2 kg is falling from rest from the top of a steep hill. What will be its kinetic energy after 5 s? (g = 10 ms–2)
Here, u=0 (because initially the object was in rest) Lets take a or g=9.8m/s^2 Now, v=u+at (first equation of motion) = v= 0+ 9.8*5 =v =49m/s Now, kinetic energy=1/2mv^2 1/2*2*49*49 =2401 joule Therefore, kinetic energy =2401 joule
