David is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, then the distance between David and his image will be (i) 3 m (ii) 5 m (iii) 6 m (iv) 8 m

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Abhishek Mishra

2 years ago

If David moves 1 m towards the mirror, then d1 = 4 − 1 = 3m Again, d1 = d2 = 3 m Therefore, the distance between David and his image is d1 + d2 = 3 + 3 = 6 m.

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