If force [F], acceleration [A ] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy. (1) [F] [A−1] [T] (2) [F] [A] [T] (3) [F] [A] [T2] (4) [F] [A] [T−1]
Option 3) Energy= FαAβTγ M1L2T−2=(MLT−2)α(LT−2)β(T)γ M1L2T−2=MαLα+βT−2α−2β+γ α=1 α+β=2 ⇒β=1 −2α−2β+γ=−2 ⇒γ=2 ⇒Energy= F1A1T2
