In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs ? (1) 62 cm (2) 60 cm (3) 21.6 cm (4) 64 cm
Option 2) Potentiometer formula \frac{e1}{e2} = \frac{l1}{l2}e2e1=l2l1 \frac{1.5}{2.5} = \frac{36}{l2}2.51.5=l236 l2 = 60 cm
