2. Equal masses of oxygen, hydrogen and methane are kept under identical conditions. The ratio of the volumes of gases will be A.2 : 16 : 2 B.2 : 16 : 1 C.1 : 16 : 2 D.1 : 1 : 1
Answer: Option C Solution: Convert the mass into moles (use the formula n=m/Mr) m = mass and Mr = Molecular weights Molecular weights are 32(Oxygen), 2(Hydrogen), and 16(Methane), respectively. Since the masses are equal, you can take the mass as x. So, the number of moles would be: n(O2) = x/32 n(H2) = x/2 n(CH4) = x/16 The ratio of their volumes is (O2) : (H2) : (CH4) = 1 : 16 : 2
