A long solenoid carrying a current produces a magnetic field B along its axis . If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is (a) B/2 (b) B (c) 2B (d) 4B

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Muskan Anand

2 years ago

Magnetic field induction at point inside the solenoid of length l, having n turns per unit length carrying current i is given by B=uoni If i is doubled, and n is having then B remains same.

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