A segment of DNA has 120 adenine and 120 cytosine bases. The total number of nucleotides present in the segment is a. 120 b. 240 c. 60 d. 480
option d. According to Chargaff's rules, the amount of adenine is always equal to that of thymine, and the amount of guanine is always equal to that of cytosine i.e A = T = 120 and G = C = 120, therefore, the total no. of nucleotides would be 120×4=480.
