The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is A. 1008 B. 1015 C. 1022 D. 1032
B) We are given that the smallest number is diminished by 7, to get divisible by all the numbers. ⇒ Required Number −7= LCM of all the numbers. Therefore, the smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is 1015.
