Electrolysis of water is a decomposition reaction. The mole ratio of hydrogen and oxygen gases liberated during electrolysis of water is: (a) 1 : 1 (b) 2:1 (c) 4:1 (d) 1:2
Correct option is B) The reaction for the dissociation of water(electrolysis) is: 2H 2 O(l)→2H 2 (g)+O 2 (g) As shown in the equation, the number of hydrogen molecules produced is twice the number of oxygen molecules. Therefore, the mole ratio of hydrogen and oxygen gas liberated is 2:1.
