A copper wire of resistivity 2.6 × 10-3 Ωm, has a cross sectional area of 30 × 10-4 cm3. Calculate the length of this wire required to make a 10 Ω coil.

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Abhishek Mishra

2 years ago

Given: R = 10Ω, ρ = 2.6 × 10-8 Ωm, To find: l = ? Formula: R = ρ L /A Solution: R = ρ L/A ∴ ρl = RA

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