3. If the point (3, 4) lies on the graph of the equation 3y = ax+7, find the value of a.
Solution The given linear equation is: 3y = ax+7 According to the given point (3, 4), x = 3 and y = 4 As this point lie on this graph, then it will satisfy these points. On substituting the values 3y = ax+7 (3 × 4) = (a × 3) + 7 12 = 3a + 7 3a = 12 – 7 3a = 5 a = 5/3
