The taxi fare in a city is as follows: For the first kilometer, the fare is ₹8 and for the subsequent distance it is ₹5 per km. Taking the distance covered as x km and total fare as ₹ y, write a linear equation for this information
Taxi fare for first kilometer = Rs. 8 Taxi fare for subsequent distance = Rs. 5 Total distance covered =x Total fare =y Since the fare for first kilometer = Rs.8 According to problem, Fare for (x–1) kilometer = 5(x−1) So, the total fare y=5(x−1)+8 ⇒y=5(x−1)+8 ⇒y=5x–5+8 ⇒y=5x+3 Hence, y=5x+3 is the required linear equation. Now the equation is y=5x+3 ...(1) Now, putting the value x=0 in (1) y=5×0+3 y=0+3=3 So the solution is (0,3) Putting the value x=1 in (1) y=5×1+3 y=5+3=8. So the solution is (1,8) Putting the value x=2 in (1) y=5×2+3 y=10+3=13. So the solution is (2,13)
