3. In Fig. 7.49, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.
Solution: In the question, it is mentioned that angles B and angle C is smaller than angles A and D respectively i.e. ∠B < ∠A and ∠C < ∠D. Now, Since the side opposite to the smaller angle is always smaller AO < BO — (i) And OD < OC —(ii) By adding equation (i) and equation (ii) we get AO+OD < BO + OC So, AD < BC
