34. What will be the normality of a solution containing 4.9 g. 43POH dissolved in 500 ml water (a) 0.3 (b) 1.0 (c) 3.0 (d) 0.1

Question

Accepted Answer

Solution : `N=(w xx 1000)/(E xx "volume in ml."),E = (98)/(3) = 32.6`
`N=(4.9xx1000)/(32.6xx500)=0.3 N`.

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