3. The active mass of 64 gm of HI in a two litre flask would be (a) 2 (b) 1 (c) 5 (d) 0.25
the expression for the active mass= no. of moles /volume in liters = mass/molar mass/volume in liter , substitute the value in above expression active mass =64/128/2=0.25 the answer is option d 0.25
