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Ananya Shree

Class 10th
Science
2 years ago

Calculate the energy transferred by a 5 A current flowing through a resistor of 2 Ω for 30 minutes.

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Muskan Anand

2 years ago

Here, I = 5 A, R = 2 Ω, t = 30 min = 1800 s Energy transferred = I2Rt = (5)2 × 2 × 1800 = 9 × 104 J.

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