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Ananya Shree

Class 10th
Science
2 years ago

A household uses the following electric appliances: (i) Refrigerator of rating 400 W for ten hours each day. (ii) Two electric fans of rating 80 W each for twelve hours each day. (iii) Six electric tubes of rating 18 W each for 6 hours each day. Calculate the electricity bill of the household for the month of June if the cost per unit of electric energy is ₹ 3.00

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Muskan Anand

2 years ago

Energy consumed by refrigerator of rating 400 W for ten hours each day = P × t = 400 W × 10 Aw = 4001000 kW × 10 h = 4.0 kWh Energy consumed by two electric fans of rating 80 W each for twelve hours each day = 2 × P × t = 2 × 80W × 12h = 1601000 kW × 12 h = 1.92 kWh Energy consumed by six electric tubes of rating 18 W each for 6 hours each day = 6 × P × t = 6 × 18W × 6h = 1081000 W × 6 h = 0.648 kWh Total energy consumed in the month of June (30 days) = (4.0 + 1.92 + 0.648) × 30 kWh = 6.568 × 30 = 197.04 kWh Electricity bill for the month of June = ₹ 197.04 × 3 = ₹ 591.12 = ₹ 591 (approx.)

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