Question 2. One mole of mono atomic gas (g = 5/3) is mixed with one mole of diatomic gas (g = 7/5) what will be the value of g for the mixture? (a) 1.5 (b) 2.5 (c) 1.0 (d) 2 Answer
For a monoatomic gas: Cv = 3R2 For a diatomic gas: Cv = 5R2 Thereofore Cvavg = 3R2+ 5R22 = 2R Also Cp = Cv + R Cpavg = 3R gamma = CpavgCvavg = 32 More
