Question 2. A particle performing uniform circular motion has angular momentum L. If its angular frequency is doubled and its kinetic energy halved, then the new angular momentum is (a) L/2 (b) L/4 (c) 2 L (d) 4 L Answer
Solution : Angular momentum, `L = I omega = I (2pi f)` <br> Frequency `f` is doubled. Hence, angular momentum will become `2L`.
