Question 3. A thin uniform, circular ring is rolling down an inclined plane of inclination 300 without slipping. Its linear acceleration along the inclined plane will be (a) g/2 (b) g/3 (c) g/4 (d) 2g/3 Answer
For ring, I = MR^2 Acceleration of a body (pure) rolling on the inclined plane, a = gsintheta1 + I/MR^2 a = gsin 301 + MR^2/MR^2 a = g4 More
