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Ananya Shree

Class 11th
Physics
2 years ago

The mass of a box measured by a grocer’s balance is 2.30 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. What is (a) the total mass of the box, (b) the difference in the masses of the pieces to correct significant figures?

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Muskan Anand

2 years ago

mi​=2.300kg ( 2 significant digits) m1​=20.15g=0.02015kg ( 4 significant digits) m2​=20.175g=0.02017kg ( 4 significant digits) (a) Adding M=Σm=2.3+0.02015+0.02017kg=2.34032kg But since the initial mass has least 2 signifincant digits, the final mass should not have more than 2 significant digits Hence, M=2.3Kg (b) Subtracting m2​−m1​=0.02g Since the initial mass has 4 significant digits, the result can have 4 or less significant digits Hence here the no. of significant digit =2

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