Measure of two quantities along with the precision of the respective measuring instrument is: A = 2.5 m/s ± 0.5 m/s B = 0.10 s ± 0.01 s The value of AB will be a) (0.25 ± 0.08) m b) (0.25 ± 0.5) m c) (0.25 ± 0.05) m d) (0.25 ± 0.135) m
Correct option is B) Here, A=2.5ms−1±0.5ms−1, B=0.10s±0.01s AB=(2.5ms−1)(0.10s)=0.25m ABΔAB=(AΔA+BΔB)=(2.50.5+0.100.01)=0.3 ΔAB=0.3×0.25m=0.075m=0.08m (Rounded off to two significant figures) The value of AB (0.25±0.8)m
