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Ananya Shree

Class 11th
Physics
2 years ago

A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed 40 m/s. Calculate the relative speed of the balls as a function of time.

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Muskan Anand

2 years ago

According to the problem, for the ball dropped from the building, u1​=0 and u2​=40m/s Velocity of the ball after time t, v1​=u1​−gt v1​=−gt And for another ball which is thrown upward, u2​=40m/s Velocity of the ball after time t, v2​=u2​−gt=(40−gt) Therefore, Relative velocity of one ball with respect to another ball is, v12​=v1​−v2​=−gt−[−40−gt] v12​=v1​−v2​=−gt+40+gt=40m/s

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