A passenger arriving in a new town wants to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min. (a) What is the average speed of the taxi? (b) What is the magnitude of average velocity? Are the two equal?
Total distance traveled = 23 km Total time taken = 28 min = 28/60 hr (a) Average speed of the taxi=Total time takenTotal distance traveled = (28/60)23 = 49.29 km/h (b) Distance between the hotel and the station = 10 km = Displacement of the car Average velocity = (28/60)10 = 21.43 km/h So, the two physical quantities (average speed and average velocity) are not equal.
