The horizontal range of a projectile fired at an angle of 15o is 50 m. If it is fired with the same speed at an angle of 45o, its range will be a) 60 m b) 71 m c) 100 m d) 141 m
Correct option is C) The horizontal range of a projectile fixed at an angle=15° Range=50m In dirst case range=50=u2/g(sin2×15°) 50=2g2gu2=100 In 2nd case range=g(sin2×45°)u2=1100(∵sin90°=1)=100m
