A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g–1 K–1; the heat of fusion of water = 335 J g–1 )
Mass of the copper block, m=2.5kg=2500g Rise in the temperature of the copper block, =500oC Specific heat of copper, C=0.39J/goC Heat of fusion of water, L=335J/g The maximum heat the copper block can lose, Q=mC =2500×0.39×500 =487500J Let m1 g be the amount of ice that melts when the copper block is placed on the ice block. The heat gained by the melted ice,Q=m1L m1=Q/L=487500/335=1455.22g Hence, the maximum amount of ice that can melt is 1.45 kg.
