If an average person jogs, he produces 14.5 × 103 cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute is assuming 1 kg requires 580 × 103 cal for evaporation a) 0.25 kg b) 2.25 kg c) 0.05 kg d) 0.20 kg
Correct option is A) Given, Calories produced per minute =14.5×103cal/min Latent heat =580×103cal/kg Amountofsweatevaporatedperminute =Numberofcaloriesrequiredforevaporation/kgSweatproduces/minute=Latentheat(incal/kg)Caloriesproduced(heatproduced)/minute =580×10314.5×103=580145=0.25kg
