1 mole of H2 gas is contained in a box of volume V = 1.00 m3 at T = 300 K. The gas is heated to a temperature of T = 3000 K and the gas gets converted to a gas of hydrogen atoms. The final pressure would be a) same as the pressure initially b) 2 times the pressure initially c) 10 times the pressure initially d) 20 times the pressure initially
Correct option is D) According to gas equation, PV=nRT or T2P2V2=T1P1V1 or P1P2=V2V1⋅T1T2 Here, T2=3000K, T1=300K Since H2 splits into hydrogen atoms, therefore volume become half i.e., V2=21V1 ∴P1P2=21V1V1×3003000 or P1P2=20
