A particle executing SHM has a maximum speed of 30 cm/s and a maximum acceleration of 60 cm/s2. The period of oscillation is a) πs b) π/2 s c) 2 πs d) π/t s
Correct option is D) Maximum velocity Vmax=Aw=30cm s−1 Maximum acceleration amax=A2w=60cm s−1 Where A=Amplitudew=angular frequency ∴A2w=60 ⟹A×30=60⟹A=2cm ∴w=230s−1=15sec−1 ∴T=w2π=152πsec
