What is the molarity of a solution of oxalic acid containing 0.63 g of it in 250 cm3 of the solution?
Oxalic Acid: C2H2O4.(2H2O ) Molar Mass : 126g Given Mass of Oxalic acid /solute = 0.63g no. of moles of solute = 0.63/126 = 0.5 *10^(-2) Volume of solution, V = 250ml = 0.25L => Molarity, M = no. of moles of solute / Volume of solution 0.5 *10^(-2) /0.25=2x10^-2 Hence,Molarity = 0.02M