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Ananya Shree

Class 11th
Physics
2 years ago
Content Issue Not Relevent Obscene Threatening Wrong Information Other

Assuming the density of water to be 1 g/cm3, calculate the volume occupied by one molecule of water.

1 Answer
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Muskan Anand

2 years ago

1 Mole of H2O = 18 g = 18 cm3[∵ density of H2O = 1 g/cm3] = 6.022 × 1023 molecules of H2O 1 Molecule will have a volume = 186.022×1023 cm- = 2.989 × 10-23 cm3

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