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Ananya Shree

Class 11th
Chemistry
1 year ago

A sample of NaNO3 weighing 0.83 g is placed in a 50,0 mL volumetric flask. The flask is then filled with water upon the etched mark. What is the molarity of the solution?

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Muskan Anand

1 year ago

Molar mass of NaNO3 = 23 + 14 + 3 × 16 = 85 g mol-1 Molarity =  Number of moles of solute  Volume of solution in L = 0.83×100085×50 = 0.196 M.

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