Calculate the number of molecules present in 350 cm3 of NH3 gas at 273 K and 2-atmosphere pressure.
Calculate the volume of the gas at STP. V1 = 350 cm3 V2 = ? T1 = 273 K T2 = 273 K P1 = 2 atm. P2 = 1 atm V2 = P1V1T1×T2P2=2×350×273273×1 = 700 cm3 22,400 cm3 of NH3 at STP contains = 6.023 × 1023 molecules of NH3 700 cm3 of NH3 at STP will contain = 1.882 × 1022 molecules.
