Calculate the energy required to convert all atoms of magnesium to magnesium ions present in 24 mg of magnesium vapors. IE1 and IE2 of Mg are 737.76 and 1450.73 kJ mol-1 respectively.
Mg (g) + IE1 → Mg+ (g) + e– (g) IE1 = 737.76 kJ mol-1 Mg+ (g) + IE2 → Mg2+ + e– (g) IE2 = 1450.73 kJ mol-1 Total amount of energy needed to convert Mg (g) into , Mg2+ ion = IE1 + IE2 Now 24 mg of Mg = 241000 g = 241000×24 mol [1 Mole of Mg = 24 g] = 10-3 mole.
