One mole of S02 gas occupied a volume of 350 mL at 27°C and 50 atm pressure. Calculate the compressibility factor of the gas. Comment on the type of deviation shown by the gas from ideal behaviour.
Compressibility factor, Z = Here n = 1, P = 50 atm, V = 350 × 10-3 L = 0.35 L R = 0.0821 L atm K-1 mol-1; T = 27 + 273 = 300 K ∴ Z = 50×0.351×0.0821×300 = 0.711 For an ideal gas Z = 1 As for the given gas Z < 1, it shows a negative deviation, i.e., it is more compressible than expected from ideal behaviour.
